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4.90x^2-25x+14=0
a = 4.90; b = -25; c = +14;
Δ = b2-4ac
Δ = -252-4·4.90·14
Δ = 350.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{350.6}}{2*4.90}=\frac{25-\sqrt{350.6}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{350.6}}{2*4.90}=\frac{25+\sqrt{350.6}}{9.8} $
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